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4013131550104 = 23501641443763
BaseRepresentation
bin111010011001100001010…
…001111100110110011000
3112012122121001000120012201
4322121201101330312120
51011222343134100404
612311335052415544
7562640066225545
oct72314121746630
915178531016181
104013131550104
111307a61157616
125499317775b4
1323158a509621
14dc34534dbcc
156e5cdc44ca4
hex3a66147cd98

4013131550104 has 8 divisors (see below), whose sum is σ = 7524621656460. Its totient is φ = 2006565775048.

The previous prime is 4013131550089. The next prime is 4013131550111. The reversal of 4013131550104 is 4010551313104.

4013131550104 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-2 number, since 2×40131315501042 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250820721874 + ... + 250820721889.

Almost surely, 24013131550104 is an apocalyptic number.

It is an amenable number.

4013131550104 is a deficient number, since it is larger than the sum of its proper divisors (3511490106356).

4013131550104 is a wasteful number, since it uses less digits than its factorization.

4013131550104 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501641443769 (or 501641443765 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 4013131550104 its reverse (4010551313104), we get a palindrome (8023682863208).

The spelling of 4013131550104 in words is "four trillion, thirteen billion, one hundred thirty-one million, five hundred fifty thousand, one hundred four".

Divisors: 1 2 4 8 501641443763 1003282887526 2006565775052 4013131550104