Base | Representation |
---|---|
bin | 10010001111111111010000… |
… | …01010110101101101110011 |
3 | 12021002120010101002101100222 |
4 | 21013333220022311231303 |
5 | 20230004333244231344 |
6 | 221204141023203255 |
7 | 11311265533505105 |
oct | 1107775012655563 |
9 | 167076111071328 |
10 | 40131774602099 |
11 | 11872876591004 |
12 | 460198214652b |
13 | 1951544008cbb |
14 | 9ca561529575 |
15 | 498dbd76d5ee |
hex | 247fe82b5b73 |
40131774602099 has 2 divisors, whose sum is σ = 40131774602100. Its totient is φ = 40131774602098.
The previous prime is 40131774602083. The next prime is 40131774602137. The reversal of 40131774602099 is 99020647713104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40131774602099 - 24 = 40131774602083 is a prime.
It is a super-3 number, since 3×401317746020993 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 40131774602099.
It is not a weakly prime, because it can be changed into another prime (40131774602069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065887301049 + 20065887301050.
It is an arithmetic number, because the mean of its divisors is an integer number (20065887301050).
Almost surely, 240131774602099 is an apocalyptic number.
40131774602099 is a deficient number, since it is larger than the sum of its proper divisors (1).
40131774602099 is an equidigital number, since it uses as much as digits as its factorization.
40131774602099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2286144, while the sum is 53.
The spelling of 40131774602099 in words is "forty trillion, one hundred thirty-one billion, seven hundred seventy-four million, six hundred two thousand, ninety-nine".
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