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40132088362787 is a prime number
BaseRepresentation
bin10010001111111111110101…
…10111101111011100100011
312021002120221020111002010012
421013333322313233130203
520230011004110102122
6221204232112155135
711311306363436231
oct1107777267573443
9167076836432105
1040132088362787
1111872a17704063
124601a4b238aab
131951594014305
149ca591081951
15498ddb0997e2
hex247ffadef723

40132088362787 has 2 divisors, whose sum is σ = 40132088362788. Its totient is φ = 40132088362786.

The previous prime is 40132088362759. The next prime is 40132088362789. The reversal of 40132088362787 is 78726388023104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40132088362787 - 210 = 40132088361763 is a prime.

It is a super-2 number, since 2×401320883627872 (a number of 28 digits) contains 22 as substring.

Together with 40132088362789, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40132088362789) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066044181393 + 20066044181394.

It is an arithmetic number, because the mean of its divisors is an integer number (20066044181394).

Almost surely, 240132088362787 is an apocalyptic number.

40132088362787 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132088362787 is an equidigital number, since it uses as much as digits as its factorization.

40132088362787 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21676032, while the sum is 59.

The spelling of 40132088362787 in words is "forty trillion, one hundred thirty-two billion, eighty-eight million, three hundred sixty-two thousand, seven hundred eighty-seven".