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4013260436543 is a prime number
BaseRepresentation
bin111010011001101000111…
…101100111010000111111
3112012122221000112200011112
4322121220331213100333
51011223124132432133
612311355535112235
7562643222601011
oct72315075472077
915178830480145
104013260436543
111308017988936
1254996897267b
132315ab1252a7
14dc3585001b1
156e5da203648
hex3a668f6743f

4013260436543 has 2 divisors, whose sum is σ = 4013260436544. Its totient is φ = 4013260436542.

The previous prime is 4013260436539. The next prime is 4013260436579. The reversal of 4013260436543 is 3456340623104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4013260436543 - 22 = 4013260436539 is a prime.

It is a super-2 number, since 2×40132604365432 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4013260436543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4013260436243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006630218271 + 2006630218272.

It is an arithmetic number, because the mean of its divisors is an integer number (2006630218272).

Almost surely, 24013260436543 is an apocalyptic number.

4013260436543 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013260436543 is an equidigital number, since it uses as much as digits as its factorization.

4013260436543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 41.

The spelling of 4013260436543 in words is "four trillion, thirteen billion, two hundred sixty million, four hundred thirty-six thousand, five hundred forty-three".