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40132634741701 is a prime number
BaseRepresentation
bin10010010000000000110110…
…11100000000101111000101
312021002122100022121000002021
421020000123130000233011
520230013113443213301
6221204402231043141
711311326046536535
oct1110003334005705
9167078308530067
1040132634741701
1111873178068687
124601b822104b1
131951650287548
149ca60386b4c5
15498e1e0248a1
hex24801b700bc5

40132634741701 has 2 divisors, whose sum is σ = 40132634741702. Its totient is φ = 40132634741700.

The previous prime is 40132634741681. The next prime is 40132634741711. The reversal of 40132634741701 is 10714743623104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29351755011076 + 10780879730625 = 5417726^2 + 3283425^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132634741701 - 29 = 40132634741189 is a prime.

It is a super-2 number, since 2×401326347417012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132634741711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066317370850 + 20066317370851.

It is an arithmetic number, because the mean of its divisors is an integer number (20066317370851).

Almost surely, 240132634741701 is an apocalyptic number.

It is an amenable number.

40132634741701 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132634741701 is an equidigital number, since it uses as much as digits as its factorization.

40132634741701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 338688, while the sum is 43.

The spelling of 40132634741701 in words is "forty trillion, one hundred thirty-two billion, six hundred thirty-four million, seven hundred forty-one thousand, seven hundred one".