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4013314640711 is a prime number
BaseRepresentation
bin111010011001101100001…
…100011000101101000111
3112012200001210112112022022
4322121230030120231013
51011223232022000321
612311405152553355
7562644451405445
oct72315414305507
915180053475268
104013314640711
111308045540272
12549982b5285b
132315b942316c
14dc3617adb95
156e5ded5ddab
hex3a66c318b47

4013314640711 has 2 divisors, whose sum is σ = 4013314640712. Its totient is φ = 4013314640710.

The previous prime is 4013314640653. The next prime is 4013314640759. The reversal of 4013314640711 is 1170464133104.

4013314640711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4013314640711 is a prime.

It is a super-2 number, since 2×40133146407112 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4013314640611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006657320355 + 2006657320356.

It is an arithmetic number, because the mean of its divisors is an integer number (2006657320356).

Almost surely, 24013314640711 is an apocalyptic number.

4013314640711 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013314640711 is an equidigital number, since it uses as much as digits as its factorization.

4013314640711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

Adding to 4013314640711 its reverse (1170464133104), we get a palindrome (5183778773815).

The spelling of 4013314640711 in words is "four trillion, thirteen billion, three hundred fourteen million, six hundred forty thousand, seven hundred eleven".