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40134104141 is a prime number
BaseRepresentation
bin100101011000001011…
…011101010001001101
310211121000101201210112
4211120023131101031
51124143312313031
630234245045405
72620363153655
oct453013352115
9124530351715
1040134104141
111602572350a
1279409b6865
133a27aa7121
141d2a319365
15109d67662b
hex9582dd44d

40134104141 has 2 divisors, whose sum is σ = 40134104142. Its totient is φ = 40134104140.

The previous prime is 40134104099. The next prime is 40134104161. The reversal of 40134104141 is 14140143104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39612940900 + 521163241 = 199030^2 + 22829^2 .

It is a cyclic number.

It is not a de Polignac number, because 40134104141 - 210 = 40134103117 is a prime.

It is a super-2 number, since 2×401341041412 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40134104161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067052070 + 20067052071.

It is an arithmetic number, because the mean of its divisors is an integer number (20067052071).

Almost surely, 240134104141 is an apocalyptic number.

It is an amenable number.

40134104141 is a deficient number, since it is larger than the sum of its proper divisors (1).

40134104141 is an equidigital number, since it uses as much as digits as its factorization.

40134104141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 40134104141 its reverse (14140143104), we get a palindrome (54274247245).

The spelling of 40134104141 in words is "forty billion, one hundred thirty-four million, one hundred four thousand, one hundred forty-one".