4013412130111 has 2 divisors, whose sum is σ = 4013412130112. Its totient is φ = 4013412130110.

The previous prime is 4013412130099. The next prime is 4013412130151. The reversal of 4013412130111 is 1110312143104.

4013412130111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4013412130111 - 2⁷ = 4013412129983 is a prime.

It is a super-2 number, since 2×4013412130111² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4013412130151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006706065055 + 2006706065056.

It is an arithmetic number, because the mean of its divisors is an integer number (2006706065056).

Almost surely, 2^{4013412130111} is an apocalyptic number.

4013412130111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013412130111 is an equidigital number, since it uses as much as digits as its factorization.

4013412130111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 4013412130111 its reverse (1110312143104), we get a palindrome (5123724273215).

The spelling of 4013412130111 in words is "four trillion, thirteen billion, four hundred twelve million, one hundred thirty thousand, one hundred eleven".