40134411040433 has 2 divisors, whose sum is σ = 40134411040434. Its totient is φ = 40134411040432.

The previous prime is 40134411040397. The next prime is 40134411040459. The reversal of 40134411040433 is 33404011443104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36065105408929 + 4069305631504 = 6005423^2 + 2017252^2 .

It is a cyclic number.

It is not a de Polignac number, because 40134411040433 - 2¹⁸ = 40134410778289 is a prime.

It is a super-2 number, since 2×40134411040433² (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40134411040433.

It is not a weakly prime, because it can be changed into another prime (40134411040133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067205520216 + 20067205520217.

It is an arithmetic number, because the mean of its divisors is an integer number (20067205520217).

Almost surely, 2^{40134411040433} is an apocalyptic number.

It is an amenable number.

40134411040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40134411040433 is an equidigital number, since it uses as much as digits as its factorization.

40134411040433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 40134411040433 its reverse (33404011443104), we get a palindrome (73538422483537).

The spelling of 40134411040433 in words is "forty trillion, one hundred thirty-four billion, four hundred eleven million, forty thousand, four hundred thirty-three".