Base | Representation |
---|---|
bin | 10010010000000100111001… |
… | …01111101101111010101111 |
3 | 12021002211221111202022000001 |
4 | 21020002130233231322233 |
5 | 20230032034331341432 |
6 | 221205401405245131 |
7 | 11311433601421606 |
oct | 1110023457557257 |
9 | 167084844668001 |
10 | 40134804168367 |
11 | 11874090705a87 |
12 | 46024888637a7 |
13 | 1951907872c6c |
14 | 9ca76ba2aa3d |
15 | 498ee97029e7 |
hex | 24809cbedeaf |
40134804168367 has 2 divisors, whose sum is σ = 40134804168368. Its totient is φ = 40134804168366.
The previous prime is 40134804168331. The next prime is 40134804168427. The reversal of 40134804168367 is 76386140843104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40134804168367 - 211 = 40134804166319 is a prime.
It is a super-2 number, since 2×401348041683672 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40134804162367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067402084183 + 20067402084184.
It is an arithmetic number, because the mean of its divisors is an integer number (20067402084184).
Almost surely, 240134804168367 is an apocalyptic number.
40134804168367 is a deficient number, since it is larger than the sum of its proper divisors (1).
40134804168367 is an equidigital number, since it uses as much as digits as its factorization.
40134804168367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9289728, while the sum is 55.
The spelling of 40134804168367 in words is "forty trillion, one hundred thirty-four billion, eight hundred four million, one hundred sixty-eight thousand, three hundred sixty-seven".
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