4013504013401 has 2 divisors, whose sum is σ = 4013504013402. Its totient is φ = 4013504013400.

The previous prime is 4013504013383. The next prime is 4013504013439. The reversal of 4013504013401 is 1043104053104.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3014473778176 + 999030235225 = 1736224^2 + 999515^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013504013401 - 2¹⁴ = 4013503997017 is a prime.

It is a super-2 number, since 2×4013504013401² (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (4013504013461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006752006700 + 2006752006701.

It is an arithmetic number, because the mean of its divisors is an integer number (2006752006701).

Almost surely, 2^{4013504013401} is an apocalyptic number.

It is an amenable number.

4013504013401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013504013401 is an equidigital number, since it uses as much as digits as its factorization.

4013504013401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 4013504013401 its reverse (1043104053104), we get a palindrome (5056608066505).

The spelling of 4013504013401 in words is "four trillion, thirteen billion, five hundred four million, thirteen thousand, four hundred one".