4013524241 has 2 divisors, whose sum is σ = 4013524242. Its totient is φ = 4013524240.

The previous prime is 4013524201. The next prime is 4013524243. The reversal of 4013524241 is 1424253104.

4013524241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2097273616 + 1916250625 = 45796^2 + 43775^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013524241 - 2²² = 4009329937 is a prime.

It is a super-2 number, since 2×4013524241² = 32216753666189252162, which contains 22 as substring.

Together with 4013524243, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4013524241.

It is not a weakly prime, because it can be changed into another prime (4013524243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006762120 + 2006762121.

It is an arithmetic number, because the mean of its divisors is an integer number (2006762121).

Almost surely, 2^4013524241 is an apocalyptic number.

It is an amenable number.

4013524241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013524241 is an equidigital number, since it uses as much as digits as its factorization.

4013524241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 26.

The square root of 4013524241 is about 63352.3814943053. The cubic root of 4013524241 is about 1589.1880723369.

Adding to 4013524241 its reverse (1424253104), we get a palindrome (5437777345).

The spelling of 4013524241 in words is "four billion, thirteen million, five hundred twenty-four thousand, two hundred forty-one".