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40135424053 is a prime number
BaseRepresentation
bin100101011000010000…
…011111100000110101
310211121002212210101011
4211120100133200311
51124144132032203
630234333232221
72620410322054
oct453020374065
9124532783334
1040135424053
111602644514a
127941332671
133a28149b3a
141d2a58039b
15109d83776d
hex95841f835

40135424053 has 2 divisors, whose sum is σ = 40135424054. Its totient is φ = 40135424052.

The previous prime is 40135424039. The next prime is 40135424101. The reversal of 40135424053 is 35042453104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26115206404 + 14020217649 = 161602^2 + 118407^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40135424053 is a prime.

It is a super-2 number, since 2×401354240532 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40135424453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067712026 + 20067712027.

It is an arithmetic number, because the mean of its divisors is an integer number (20067712027).

Almost surely, 240135424053 is an apocalyptic number.

It is an amenable number.

40135424053 is a deficient number, since it is larger than the sum of its proper divisors (1).

40135424053 is an equidigital number, since it uses as much as digits as its factorization.

40135424053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 40135424053 its reverse (35042453104), we get a palindrome (75177877157).

The spelling of 40135424053 in words is "forty billion, one hundred thirty-five million, four hundred twenty-four thousand, fifty-three".