40137447844211 has 2 divisors, whose sum is σ = 40137447844212. Its totient is φ = 40137447844210.

The previous prime is 40137447844157. The next prime is 40137447844213. The reversal of 40137447844211 is 11244874473104.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40137447844211 is a prime.

It is a super-2 number, since 2×40137447844211² (a number of 28 digits) contains 22 as substring.

Together with 40137447844213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40137447844211.

It is not a weakly prime, because it can be changed into another prime (40137447844213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20068723922105 + 20068723922106.

It is an arithmetic number, because the mean of its divisors is an integer number (20068723922106).

Almost surely, 2^{40137447844211} is an apocalyptic number.

40137447844211 is a deficient number, since it is larger than the sum of its proper divisors (1).

40137447844211 is an equidigital number, since it uses as much as digits as its factorization.

40137447844211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2408448, while the sum is 50.

The spelling of 40137447844211 in words is "forty trillion, one hundred thirty-seven billion, four hundred forty-seven million, eight hundred forty-four thousand, two hundred eleven".