Base | Representation |
---|---|
bin | 1011101011101010101… |
… | …00110010011100101001 |
3 | 1102101002021120010111221 |
4 | 11311311110302130221 |
5 | 23034031441423223 |
6 | 504222322222041 |
7 | 41000034420445 |
oct | 5656524623451 |
9 | 1371067503457 |
10 | 401400342313 |
11 | 1452620352a3 |
12 | 659641b4921 |
13 | 2bb0c7a9869 |
14 | 155dc163825 |
15 | a694809b5d |
hex | 5d75532729 |
401400342313 has 2 divisors, whose sum is σ = 401400342314. Its totient is φ = 401400342312.
The previous prime is 401400342251. The next prime is 401400342353. The reversal of 401400342313 is 313243004104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 400445964864 + 954377449 = 632808^2 + 30893^2 .
It is a cyclic number.
It is not a de Polignac number, because 401400342313 - 229 = 400863471401 is a prime.
It is a super-2 number, since 2×4014003423132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (401400342353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200700171156 + 200700171157.
It is an arithmetic number, because the mean of its divisors is an integer number (200700171157).
Almost surely, 2401400342313 is an apocalyptic number.
It is an amenable number.
401400342313 is a deficient number, since it is larger than the sum of its proper divisors (1).
401400342313 is an equidigital number, since it uses as much as digits as its factorization.
401400342313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 401400342313 its reverse (313243004104), we get a palindrome (714643346417).
The spelling of 401400342313 in words is "four hundred one billion, four hundred million, three hundred forty-two thousand, three hundred thirteen".
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