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4014020441131 is a prime number
BaseRepresentation
bin111010011010010110010…
…000110011010000101011
3112012201212222121220110121
4322122112100303100223
51011231203213104011
612312003204424111
7563001111535561
oct72322620632053
915181788556417
104014020441131
1113083779915a8
12549b3b3a8037
1323169c71374c
14dc3cb417a31
156e631cc9e71
hex3a69643342b

4014020441131 has 2 divisors, whose sum is σ = 4014020441132. Its totient is φ = 4014020441130.

The previous prime is 4014020441111. The next prime is 4014020441153. The reversal of 4014020441131 is 1311440204104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4014020441131 - 219 = 4014019916843 is a prime.

It is a super-2 number, since 2×40140204411312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4014020441096 and 4014020441105.

It is not a weakly prime, because it can be changed into another prime (4014020441111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007010220565 + 2007010220566.

It is an arithmetic number, because the mean of its divisors is an integer number (2007010220566).

Almost surely, 24014020441131 is an apocalyptic number.

4014020441131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014020441131 is an equidigital number, since it uses as much as digits as its factorization.

4014020441131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4014020441131 its reverse (1311440204104), we get a palindrome (5325460645235).

The spelling of 4014020441131 in words is "four trillion, fourteen billion, twenty million, four hundred forty-one thousand, one hundred thirty-one".