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4014311211241 is a prime number
BaseRepresentation
bin111010011010100111100…
…110000000000011101001
3112012202122020202120001221
4322122213212000003221
51011232302132224431
612312052112542041
7563011242204052
oct72324746000351
915182566676057
104014311211241
111308507031481
1254a000851921
13231717a2c376
14dc417ca7729
156e64c5b4111
hex3a6a79800e9

4014311211241 has 2 divisors, whose sum is σ = 4014311211242. Its totient is φ = 4014311211240.

The previous prime is 4014311211233. The next prime is 4014311211247. The reversal of 4014311211241 is 1421121134104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3819679360000 + 194631851241 = 1954400^2 + 441171^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014311211241 - 23 = 4014311211233 is a prime.

It is a super-2 number, since 2×40143112112412 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4014311211247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007155605620 + 2007155605621.

It is an arithmetic number, because the mean of its divisors is an integer number (2007155605621).

Almost surely, 24014311211241 is an apocalyptic number.

It is an amenable number.

4014311211241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014311211241 is an equidigital number, since it uses as much as digits as its factorization.

4014311211241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 4014311211241 its reverse (1421121134104), we get a palindrome (5435432345345).

The spelling of 4014311211241 in words is "four trillion, fourteen billion, three hundred eleven million, two hundred eleven thousand, two hundred forty-one".