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40143320445001 is a prime number
BaseRepresentation
bin10010010000010100110000…
…10110101111000001001001
312021010122221000121222022011
421020022120112233001021
520230202010013220001
6221213330430455521
711312154621526504
oct1110123026570111
9167118830558264
1040143320445001
1111877760947734
1246040649645a1
1319526640498c7
149cad38ac613b
154993471cdd51
hex2482985af049

40143320445001 has 2 divisors, whose sum is σ = 40143320445002. Its totient is φ = 40143320445000.

The previous prime is 40143320444999. The next prime is 40143320445037. The reversal of 40143320445001 is 10054402334104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38644263035401 + 1499057409600 = 6216451^2 + 1224360^2 .

It is a cyclic number.

It is not a de Polignac number, because 40143320445001 - 21 = 40143320444999 is a prime.

It is a super-2 number, since 2×401433204450012 (a number of 28 digits) contains 22 as substring.

Together with 40143320444999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (40143320445601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20071660222500 + 20071660222501.

It is an arithmetic number, because the mean of its divisors is an integer number (20071660222501).

Almost surely, 240143320445001 is an apocalyptic number.

It is an amenable number.

40143320445001 is a deficient number, since it is larger than the sum of its proper divisors (1).

40143320445001 is an equidigital number, since it uses as much as digits as its factorization.

40143320445001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 40143320445001 its reverse (10054402334104), we get a palindrome (50197722779105).

The spelling of 40143320445001 in words is "forty trillion, one hundred forty-three billion, three hundred twenty million, four hundred forty-five thousand, one".