Base | Representation |
---|---|
bin | 10010010000010110000110… |
… | …11101100100000101110011 |
3 | 12021010201210102110212122122 |
4 | 21020023003131210011303 |
5 | 20230210000133434124 |
6 | 221213530303424455 |
7 | 11312211552651155 |
oct | 1110130335440563 |
9 | 167121712425578 |
10 | 40144043655539 |
11 | 11877aa20aa49a |
12 | 4604226bb512b |
13 | 195274ab24835 |
14 | 9cada6b82ad5 |
15 | 49938a93875e |
hex | 2482c3764173 |
40144043655539 has 2 divisors, whose sum is σ = 40144043655540. Its totient is φ = 40144043655538.
The previous prime is 40144043655439. The next prime is 40144043655553. The reversal of 40144043655539 is 93555634044104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40144043655539 - 212 = 40144043651443 is a prime.
It is a super-2 number, since 2×401440436555392 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40144043655439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20072021827769 + 20072021827770.
It is an arithmetic number, because the mean of its divisors is an integer number (20072021827770).
Almost surely, 240144043655539 is an apocalyptic number.
40144043655539 is a deficient number, since it is larger than the sum of its proper divisors (1).
40144043655539 is an equidigital number, since it uses as much as digits as its factorization.
40144043655539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 53.
The spelling of 40144043655539 in words is "forty trillion, one hundred forty-four billion, forty-three million, six hundred fifty-five thousand, five hundred thirty-nine".
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