40151210143133 has 2 divisors, whose sum is σ = 40151210143134. Its totient is φ = 40151210143132.

The previous prime is 40151210143123. The next prime is 40151210143147. The reversal of 40151210143133 is 33134101215104.

40151210143133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33335126700964 + 6816083442169 = 5773658^2 + 2610763^2 .

It is a cyclic number.

It is not a de Polignac number, because 40151210143133 - 2⁴ = 40151210143117 is a prime.

It is a super-2 number, since 2×40151210143133² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40151210143096 and 40151210143105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40151210143123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20075605071566 + 20075605071567.

It is an arithmetic number, because the mean of its divisors is an integer number (20075605071567).

Almost surely, 2^{40151210143133} is an apocalyptic number.

It is an amenable number.

40151210143133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40151210143133 is an equidigital number, since it uses as much as digits as its factorization.

40151210143133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 40151210143133 its reverse (33134101215104), we get a palindrome (73285311358237).

The spelling of 40151210143133 in words is "forty trillion, one hundred fifty-one billion, two hundred ten million, one hundred forty-three thousand, one hundred thirty-three".