Base | Representation |
---|---|
bin | 100101011001010000… |
… | …000110110110000111 |
3 | 10211122021021000210101 |
4 | 211121100012312013 |
5 | 1124212414201411 |
6 | 30240130504531 |
7 | 2621002135465 |
oct | 453120066607 |
9 | 124567230711 |
10 | 40152100231 |
11 | 160348a5211 |
12 | 7946a35147 |
13 | 3a2b7383b9 |
14 | 1d2c881835 |
15 | 10a002d8c1 |
hex | 959406d87 |
40152100231 has 2 divisors, whose sum is σ = 40152100232. Its totient is φ = 40152100230.
The previous prime is 40152100213. The next prime is 40152100319. The reversal of 40152100231 is 13200125104.
Together with previous prime (40152100213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40152100231 - 27 = 40152100103 is a prime.
It is a super-2 number, since 2×401521002312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40152100199 and 40152100208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40152100931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20076050115 + 20076050116.
It is an arithmetic number, because the mean of its divisors is an integer number (20076050116).
Almost surely, 240152100231 is an apocalyptic number.
40152100231 is a deficient number, since it is larger than the sum of its proper divisors (1).
40152100231 is an equidigital number, since it uses as much as digits as its factorization.
40152100231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 40152100231 its reverse (13200125104), we get a palindrome (53352225335).
The spelling of 40152100231 in words is "forty billion, one hundred fifty-two million, one hundred thousand, two hundred thirty-one".
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