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40157142133 is a prime number
BaseRepresentation
bin100101011001100011…
…010101110001110101
310211122121202011222111
4211121203111301311
51124220212022013
630240430531021
72621063035063
oct453143256165
9124577664874
1040157142133
1116037729279
127948666a71
133a2c7b2284
141d2d3d5033
1510a06c773d
hex9598d5c75

40157142133 has 2 divisors, whose sum is σ = 40157142134. Its totient is φ = 40157142132.

The previous prime is 40157142089. The next prime is 40157142139. The reversal of 40157142133 is 33124175104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30463164369 + 9693977764 = 174537^2 + 98458^2 .

It is a cyclic number.

It is not a de Polignac number, because 40157142133 - 213 = 40157133941 is a prime.

It is a super-2 number, since 2×401571421332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40157142095 and 40157142104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40157142139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20078571066 + 20078571067.

It is an arithmetic number, because the mean of its divisors is an integer number (20078571067).

Almost surely, 240157142133 is an apocalyptic number.

It is an amenable number.

40157142133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40157142133 is an equidigital number, since it uses as much as digits as its factorization.

40157142133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 40157142133 in words is "forty billion, one hundred fifty-seven million, one hundred forty-two thousand, one hundred thirty-three".