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40163630381713 is a prime number
BaseRepresentation
bin10010010000111010100101…
…11010111111101010010001
312021012121100110100122210101
421020131102322333222101
520231020103334203323
6221230530031132401
711313504126250126
oct1110352272775221
9167177313318711
1040163630381713
11118853333177a3
124607b92674101
13195454c9c1137
149cbd0420a74d
15499b3526cdad
hex248752ebfa91

40163630381713 has 2 divisors, whose sum is σ = 40163630381714. Its totient is φ = 40163630381712.

The previous prime is 40163630381711. The next prime is 40163630381723. The reversal of 40163630381713 is 31718303636104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33011091998784 + 7152538382929 = 5745528^2 + 2674423^2 .

It is a cyclic number.

It is not a de Polignac number, because 40163630381713 - 21 = 40163630381711 is a prime.

It is a super-2 number, since 2×401636303817132 (a number of 28 digits) contains 22 as substring.

Together with 40163630381711, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (40163630381711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20081815190856 + 20081815190857.

It is an arithmetic number, because the mean of its divisors is an integer number (20081815190857).

Almost surely, 240163630381713 is an apocalyptic number.

It is an amenable number.

40163630381713 is a deficient number, since it is larger than the sum of its proper divisors (1).

40163630381713 is an equidigital number, since it uses as much as digits as its factorization.

40163630381713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 46.

The spelling of 40163630381713 in words is "forty trillion, one hundred sixty-three billion, six hundred thirty million, three hundred eighty-one thousand, seven hundred thirteen".