Base | Representation |
---|---|
bin | 101101101011010011000100… |
… | …1100010100111000111011111 |
3 | 1221200120022120011200020002001 |
4 | 1123112212021202213013133 |
5 | 410130140221423143111 |
6 | 3542300521515343131 |
7 | 150425200422442015 |
oct | 13326461142470737 |
9 | 1850508504606061 |
10 | 401775023256031 |
11 | 107021915413917 |
12 | 3908a836451aa7 |
13 | 143252b700cbc9 |
14 | 713002cba48b5 |
15 | 316b15505a1c1 |
hex | 16d69898a71df |
401775023256031 has 2 divisors, whose sum is σ = 401775023256032. Its totient is φ = 401775023256030.
The previous prime is 401775023255993. The next prime is 401775023256067. The reversal of 401775023256031 is 130652320577104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-401775023256031 is a prime.
It is a super-3 number, since 3×4017750232560313 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401775023236031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200887511628015 + 200887511628016.
It is an arithmetic number, because the mean of its divisors is an integer number (200887511628016).
Almost surely, 2401775023256031 is an apocalyptic number.
401775023256031 is a deficient number, since it is larger than the sum of its proper divisors (1).
401775023256031 is an equidigital number, since it uses as much as digits as its factorization.
401775023256031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1058400, while the sum is 46.
The spelling of 401775023256031 in words is "four hundred one trillion, seven hundred seventy-five billion, twenty-three million, two hundred fifty-six thousand, thirty-one".
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