Base | Representation |
---|---|
bin | 1011101100110111010… |
… | …00111001000100110111 |
3 | 1102102202002002222011022 |
4 | 11312123220321010313 |
5 | 23041341021142201 |
6 | 504410203531355 |
7 | 41022001234334 |
oct | 5663350710467 |
9 | 1372662088138 |
10 | 402043146551 |
11 | 145561969672 |
12 | 65b03529b5b |
13 | 2bbb2a114b7 |
14 | 1565d68d98b |
15 | a6d0e8041b |
hex | 5d9ba39137 |
402043146551 has 2 divisors, whose sum is σ = 402043146552. Its totient is φ = 402043146550.
The previous prime is 402043146511. The next prime is 402043146577. The reversal of 402043146551 is 155641340204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 402043146551 - 234 = 384863277367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (402043146511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201021573275 + 201021573276.
It is an arithmetic number, because the mean of its divisors is an integer number (201021573276).
Almost surely, 2402043146551 is an apocalyptic number.
402043146551 is a deficient number, since it is larger than the sum of its proper divisors (1).
402043146551 is an equidigital number, since it uses as much as digits as its factorization.
402043146551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 402043146551 its reverse (155641340204), we get a palindrome (557684486755).
The spelling of 402043146551 in words is "four hundred two billion, forty-three million, one hundred forty-six thousand, five hundred fifty-one".
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