Base | Representation |
---|---|
bin | 111010100001000011000… |
… | …010001111101011101111 |
3 | 112020102110022200011010210 |
4 | 322201003002033223233 |
5 | 1011340421244113210 |
6 | 12315153100433503 |
7 | 563344301316345 |
oct | 72410302175357 |
9 | 15212408604123 |
10 | 4021214051055 |
11 | 1310429554173 |
12 | 54b408548893 |
13 | 232277b77276 |
14 | dc8b0971995 |
15 | 6e9035d9e20 |
hex | 3a84308faef |
4021214051055 has 64 divisors (see below), whose sum is σ = 6544170247680. Its totient is φ = 2108049732096.
The previous prime is 4021214051047. The next prime is 4021214051279. The reversal of 4021214051055 is 5501504121204.
It is not a de Polignac number, because 4021214051055 - 23 = 4021214051047 is a prime.
It is a super-2 number, since 2×40212140510552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1719201076 + ... + 1719203414.
It is an arithmetic number, because the mean of its divisors is an integer number (102252660120).
Almost surely, 24021214051055 is an apocalyptic number.
4021214051055 is a deficient number, since it is larger than the sum of its proper divisors (2522956196625).
4021214051055 is a wasteful number, since it uses less digits than its factorization.
4021214051055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5400.
The product of its (nonzero) digits is 8000, while the sum is 30.
Adding to 4021214051055 its reverse (5501504121204), we get a palindrome (9522718172259).
The spelling of 4021214051055 in words is "four trillion, twenty-one billion, two hundred fourteen million, fifty-one thousand, fifty-five".
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