Base | Representation |
---|---|
bin | 111010100001000011111… |
… | …111001111100000110111 |
3 | 112020102111102202112102021 |
4 | 322201003333033200313 |
5 | 1011340434342304033 |
6 | 12315154431254011 |
7 | 563344554244600 |
oct | 72410377174067 |
9 | 15212442675367 |
10 | 4021230041143 |
11 | 1310437585817 |
12 | 54b41197a307 |
13 | 23227b285463 |
14 | dc8b2b34da7 |
15 | 6e904be7b2d |
hex | 3a843fcf837 |
4021230041143 has 96 divisors (see below), whose sum is σ = 5031959708160. Its totient is φ = 3197966042880.
The previous prime is 4021230041119. The next prime is 4021230041173. The reversal of 4021230041143 is 3411400321204.
It is not a de Polignac number, because 4021230041143 - 221 = 4021227943991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4021230041173) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3457634880 + ... + 3457636042.
It is an arithmetic number, because the mean of its divisors is an integer number (52416246960).
Almost surely, 24021230041143 is an apocalyptic number.
4021230041143 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
4021230041143 is a deficient number, since it is larger than the sum of its proper divisors (1010729667017).
4021230041143 is a wasteful number, since it uses less digits than its factorization.
4021230041143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2117 (or 2110 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4021230041143 its reverse (3411400321204), we get a palindrome (7432630362347).
The spelling of 4021230041143 in words is "four trillion, twenty-one billion, two hundred thirty million, forty-one thousand, one hundred forty-three".
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