Base | Representation |
---|---|
bin | 111010100001001111011… |
… | …111110101110110100111 |
3 | 112020102222220002202222211 |
4 | 322201033133311312213 |
5 | 1011341333310324132 |
6 | 12315225530104251 |
7 | 563352420443053 |
oct | 72411737656647 |
9 | 15212886082884 |
10 | 4021423136167 |
11 | 1310526581988 |
12 | 54b46657b087 |
13 | 2322ac292878 |
14 | dc8d063ac63 |
15 | 6e916b3b147 |
hex | 3a84f7f5da7 |
4021423136167 has 2 divisors, whose sum is σ = 4021423136168. Its totient is φ = 4021423136166.
The previous prime is 4021423136147. The next prime is 4021423136179. The reversal of 4021423136167 is 7616313241204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021423136167 - 231 = 4019275652519 is a prime.
It is a super-3 number, since 3×40214231361673 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4021423136147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010711568083 + 2010711568084.
It is an arithmetic number, because the mean of its divisors is an integer number (2010711568084).
Almost surely, 24021423136167 is an apocalyptic number.
4021423136167 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021423136167 is an equidigital number, since it uses as much as digits as its factorization.
4021423136167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 4021423136167 in words is "four trillion, twenty-one billion, four hundred twenty-three million, one hundred thirty-six thousand, one hundred sixty-seven".
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