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402142532471 is a prime number
BaseRepresentation
bin1011101101000011001…
…00000001001101110111
31102110000000010022000022
411312201210001031313
523042041442014341
6504424114035355
741024316061241
oct5664144011567
91373000108008
10402142532471
11145602a80799
1265b30878b5b
132bbca49b634
141566c961091
15a6d9a62e4b
hex5da1901377

402142532471 has 2 divisors, whose sum is σ = 402142532472. Its totient is φ = 402142532470.

The previous prime is 402142532353. The next prime is 402142532527. The reversal of 402142532471 is 174235241204.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-402142532471 is a prime.

It is a super-3 number, since 3×4021425324713 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402142531471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201071266235 + 201071266236.

It is an arithmetic number, because the mean of its divisors is an integer number (201071266236).

Almost surely, 2402142532471 is an apocalyptic number.

402142532471 is a deficient number, since it is larger than the sum of its proper divisors (1).

402142532471 is an equidigital number, since it uses as much as digits as its factorization.

402142532471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 53760, while the sum is 35.

Adding to 402142532471 its reverse (174235241204), we get a palindrome (576377773675).

The spelling of 402142532471 in words is "four hundred two billion, one hundred forty-two million, five hundred thirty-two thousand, four hundred seventy-one".