Base | Representation |
---|---|
bin | 111010100001110001111… |
… | …100101011001101111001 |
3 | 112020111111011200101220221 |
4 | 322201301330223031321 |
5 | 1011344024241320441 |
6 | 12315403134220041 |
7 | 563402636305345 |
oct | 72416174531571 |
9 | 15214434611827 |
10 | 4022001120121 |
11 | 13107a2862876 |
12 | 54b5a8054621 |
13 | 232371c504ca |
14 | dc9472d2625 |
15 | 6e94c75a8d1 |
hex | 3a871f2b379 |
4022001120121 has 2 divisors, whose sum is σ = 4022001120122. Its totient is φ = 4022001120120.
The previous prime is 4022001120103. The next prime is 4022001120133. The reversal of 4022001120121 is 1210211002204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3656049926400 + 365951193721 = 1912080^2 + 604939^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022001120121 - 213 = 4022001111929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4022001120095 and 4022001120104.
It is not a weakly prime, because it can be changed into another prime (4022001120191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011000560060 + 2011000560061.
It is an arithmetic number, because the mean of its divisors is an integer number (2011000560061).
Almost surely, 24022001120121 is an apocalyptic number.
It is an amenable number.
4022001120121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022001120121 is an equidigital number, since it uses as much as digits as its factorization.
4022001120121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 4022001120121 its reverse (1210211002204), we get a palindrome (5232212122325).
The spelling of 4022001120121 in words is "four trillion, twenty-two billion, one million, one hundred twenty thousand, one hundred twenty-one".
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