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402212113 is a prime number
BaseRepresentation
bin10111111110010…
…100010100010001
31001000211111021221
4113332110110101
51310431241423
6103524445041
712652514032
oct2776242421
91030744257
10402212113
11197046a06
12b2849781
1365437444
143b5bca89
152549de5d
hex17f94511

402212113 has 2 divisors, whose sum is σ = 402212114. Its totient is φ = 402212112.

The previous prime is 402212081. The next prime is 402212123. The reversal of 402212113 is 311212204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 391564944 + 10647169 = 19788^2 + 3263^2 .

It is a cyclic number.

It is not a de Polignac number, because 402212113 - 25 = 402212081 is a prime.

It is not a weakly prime, because it can be changed into another prime (402212123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201106056 + 201106057.

It is an arithmetic number, because the mean of its divisors is an integer number (201106057).

Almost surely, 2402212113 is an apocalyptic number.

It is an amenable number.

402212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

402212113 is an equidigital number, since it uses as much as digits as its factorization.

402212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 402212113 is about 20055.2265756336. The cubic root of 402212113 is about 738.1620525541.

Adding to 402212113 its reverse (311212204), we get a palindrome (713424317).

Subtracting from 402212113 its reverse (311212204), we obtain a palindrome (90999909).

The spelling of 402212113 in words is "four hundred two million, two hundred twelve thousand, one hundred thirteen".