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40221214153 is a prime number
BaseRepresentation
bin100101011101010111…
…110000010111001001
310211211002022101021021
4211131113300113021
51124333112323103
630251040112441
72622501452011
oct453527602711
9124732271237
1040221214153
111606a91055a
127966005721
133a3cb56803
141d37b12c41
1510a6131bbd
hex95d5f05c9

40221214153 has 2 divisors, whose sum is σ = 40221214154. Its totient is φ = 40221214152.

The previous prime is 40221214123. The next prime is 40221214177. The reversal of 40221214153 is 35141212204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30210611344 + 10010602809 = 173812^2 + 100053^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40221214153 is a prime.

It is not a weakly prime, because it can be changed into another prime (40221214123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20110607076 + 20110607077.

It is an arithmetic number, because the mean of its divisors is an integer number (20110607077).

Almost surely, 240221214153 is an apocalyptic number.

It is an amenable number.

40221214153 is a deficient number, since it is larger than the sum of its proper divisors (1).

40221214153 is an equidigital number, since it uses as much as digits as its factorization.

40221214153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 40221214153 its reverse (35141212204), we get a palindrome (75362426357).

The spelling of 40221214153 in words is "forty billion, two hundred twenty-one million, two hundred fourteen thousand, one hundred fifty-three".