Base | Representation |
---|---|
bin | 10010010010100110000000… |
… | …10011100110010111111101 |
3 | 12021102010012120011001201021 |
4 | 21021103000103212113331 |
5 | 20232441210312420013 |
6 | 221313224333544141 |
7 | 11320615212050053 |
oct | 1111230023462775 |
9 | 167363176131637 |
10 | 40221300123133 |
11 | 118a7837397018 |
12 | 46171a8045051 |
13 | 1959b1074059c |
14 | 9d0a153d61d3 |
15 | 49b3ad123a8d |
hex | 2494c04e65fd |
40221300123133 has 8 divisors (see below), whose sum is σ = 41580974861888. Its totient is φ = 38880911551104.
The previous prime is 40221300123127. The next prime is 40221300123139. The reversal of 40221300123133 is 33132100312204.
It is an interprime number because it is at equal distance from previous prime (40221300123127) and next prime (40221300123139).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 40221300123133 - 229 = 40220763252221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40221300123098 and 40221300123107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40221300123139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4821537441 + ... + 4821545782.
It is an arithmetic number, because the mean of its divisors is an integer number (5197621857736).
Almost surely, 240221300123133 is an apocalyptic number.
40221300123133 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
40221300123133 is a deficient number, since it is larger than the sum of its proper divisors (1359674738755).
40221300123133 is an equidigital number, since it uses as much as digits as its factorization.
40221300123133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9643083363.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 40221300123133 its reverse (33132100312204), we get a palindrome (73353400435337).
The spelling of 40221300123133 in words is "forty trillion, two hundred twenty-one billion, three hundred million, one hundred twenty-three thousand, one hundred thirty-three".
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