Base | Representation |
---|---|
bin | 111010100001111001101… |
… | …101010100101011111001 |
3 | 112020111211020122220112021 |
4 | 322201321231110223321 |
5 | 1011344311104012101 |
6 | 12315424104514441 |
7 | 563406110032525 |
oct | 72417155245371 |
9 | 15214736586467 |
10 | 4022131313401 |
11 | 131085a2a6a23 |
12 | 54b62377ba21 |
13 | 232392c05c56 |
14 | dc95a702d85 |
15 | 6e958dc65a1 |
hex | 3a879b54af9 |
4022131313401 has 2 divisors, whose sum is σ = 4022131313402. Its totient is φ = 4022131313400.
The previous prime is 4022131313371. The next prime is 4022131313407. The reversal of 4022131313401 is 1043131312204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2714664845376 + 1307466468025 = 1647624^2 + 1143445^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022131313401 - 223 = 4022122924793 is a prime.
It is not a weakly prime, because it can be changed into another prime (4022131313407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011065656700 + 2011065656701.
It is an arithmetic number, because the mean of its divisors is an integer number (2011065656701).
Almost surely, 24022131313401 is an apocalyptic number.
It is an amenable number.
4022131313401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022131313401 is an equidigital number, since it uses as much as digits as its factorization.
4022131313401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4022131313401 its reverse (1043131312204), we get a palindrome (5065262625605).
The spelling of 4022131313401 in words is "four trillion, twenty-two billion, one hundred thirty-one million, three hundred thirteen thousand, four hundred one".
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