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40221400232131 is a prime number
BaseRepresentation
bin10010010010100110001100…
…10001011111000011000011
312021102010110112112010102221
421021103012101133003003
520232441411424412011
6221313242311351511
711320620536005036
oct1111230621370303
9167363415463387
1040221400232131
11118a7888952428
124617215682597
131959b283c1891
149d0a2481501d
1549b3b6cea971
hex2494c645f0c3

40221400232131 has 2 divisors, whose sum is σ = 40221400232132. Its totient is φ = 40221400232130.

The previous prime is 40221400232071. The next prime is 40221400232137. The reversal of 40221400232131 is 13123200412204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40221400232131 - 211 = 40221400230083 is a prime.

It is a super-2 number, since 2×402214002321312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40221400232096 and 40221400232105.

It is not a weakly prime, because it can be changed into another prime (40221400232137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20110700116065 + 20110700116066.

It is an arithmetic number, because the mean of its divisors is an integer number (20110700116066).

Almost surely, 240221400232131 is an apocalyptic number.

40221400232131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40221400232131 is an equidigital number, since it uses as much as digits as its factorization.

40221400232131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 40221400232131 its reverse (13123200412204), we get a palindrome (53344600644335).

The spelling of 40221400232131 in words is "forty trillion, two hundred twenty-one billion, four hundred million, two hundred thirty-two thousand, one hundred thirty-one".