Base | Representation |
---|---|
bin | 10010010010100110001100… |
… | …10001011111000011000011 |
3 | 12021102010110112112010102221 |
4 | 21021103012101133003003 |
5 | 20232441411424412011 |
6 | 221313242311351511 |
7 | 11320620536005036 |
oct | 1111230621370303 |
9 | 167363415463387 |
10 | 40221400232131 |
11 | 118a7888952428 |
12 | 4617215682597 |
13 | 1959b283c1891 |
14 | 9d0a2481501d |
15 | 49b3b6cea971 |
hex | 2494c645f0c3 |
40221400232131 has 2 divisors, whose sum is σ = 40221400232132. Its totient is φ = 40221400232130.
The previous prime is 40221400232071. The next prime is 40221400232137. The reversal of 40221400232131 is 13123200412204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40221400232131 - 211 = 40221400230083 is a prime.
It is a super-2 number, since 2×402214002321312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40221400232096 and 40221400232105.
It is not a weakly prime, because it can be changed into another prime (40221400232137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20110700116065 + 20110700116066.
It is an arithmetic number, because the mean of its divisors is an integer number (20110700116066).
Almost surely, 240221400232131 is an apocalyptic number.
40221400232131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40221400232131 is an equidigital number, since it uses as much as digits as its factorization.
40221400232131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 40221400232131 its reverse (13123200412204), we get a palindrome (53344600644335).
The spelling of 40221400232131 in words is "forty trillion, two hundred twenty-one billion, four hundred million, two hundred thirty-two thousand, one hundred thirty-one".
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