Base | Representation |
---|---|
bin | 111010100010101101101… |
… | …010111110011010111011 |
3 | 112020121002000002220221202 |
4 | 322202231222332122323 |
5 | 1011403102244110042 |
6 | 12320050410324415 |
7 | 563436524146664 |
oct | 72425552763273 |
9 | 15217060086852 |
10 | 4023003113147 |
11 | 1311167417a87 |
12 | 54b82772970b |
13 | 2324a17078a5 |
14 | dca003dc36b |
15 | 6e9aa6d2632 |
hex | 3a8adabe6bb |
4023003113147 has 2 divisors, whose sum is σ = 4023003113148. Its totient is φ = 4023003113146.
The previous prime is 4023003113029. The next prime is 4023003113161. The reversal of 4023003113147 is 7413113003204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4023003113147 - 228 = 4022734677691 is a prime.
It is not a weakly prime, because it can be changed into another prime (4023003113177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011501556573 + 2011501556574.
It is an arithmetic number, because the mean of its divisors is an integer number (2011501556574).
Almost surely, 24023003113147 is an apocalyptic number.
4023003113147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023003113147 is an equidigital number, since it uses as much as digits as its factorization.
4023003113147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 4023003113147 in words is "four trillion, twenty-three billion, three million, one hundred thirteen thousand, one hundred forty-seven".
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