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4023003113161 is a prime number
BaseRepresentation
bin111010100010101101101…
…010111110011011001001
3112020121002000002220222021
4322202231222332123021
51011403102244110121
612320050410324441
7563436524150014
oct72425552763311
915217060086867
104023003113161
111311167417a9a
1254b827729721
132324a17078b6
14dca003dc37b
156e9aa6d2641
hex3a8adabe6c9

4023003113161 has 2 divisors, whose sum is σ = 4023003113162. Its totient is φ = 4023003113160.

The previous prime is 4023003113147. The next prime is 4023003113177. The reversal of 4023003113161 is 1613113003204.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3221899351225 + 801103761936 = 1794965^2 + 895044^2 .

It is a cyclic number.

It is not a de Polignac number, because 4023003113161 - 213 = 4023003104969 is a prime.

It is not a weakly prime, because it can be changed into another prime (4023003114161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011501556580 + 2011501556581.

It is an arithmetic number, because the mean of its divisors is an integer number (2011501556581).

Almost surely, 24023003113161 is an apocalyptic number.

It is an amenable number.

4023003113161 is a deficient number, since it is larger than the sum of its proper divisors (1).

4023003113161 is an equidigital number, since it uses as much as digits as its factorization.

4023003113161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 4023003113161 its reverse (1613113003204), we get a palindrome (5636116116365).

The spelling of 4023003113161 in words is "four trillion, twenty-three billion, three million, one hundred thirteen thousand, one hundred sixty-one".