Base | Representation |
---|---|
bin | 111010100010101111011… |
… | …001100110110011100001 |
3 | 112020121011000200100012021 |
4 | 322202233121212303201 |
5 | 1011403132210130101 |
6 | 12320053324101441 |
7 | 563440325515516 |
oct | 72425731466341 |
9 | 15217130610167 |
10 | 4023032114401 |
11 | 1311181826063 |
12 | 54b835394881 |
13 | 2324a77200b1 |
14 | dca041cb30d |
15 | 6e9ad0105a1 |
hex | 3a8af666ce1 |
4023032114401 has 2 divisors, whose sum is σ = 4023032114402. Its totient is φ = 4023032114400.
The previous prime is 4023032114389. The next prime is 4023032114443. The reversal of 4023032114401 is 1044112303204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3918024360000 + 105007754401 = 1979400^2 + 324049^2 .
It is a cyclic number.
It is not a de Polignac number, because 4023032114401 - 25 = 4023032114369 is a prime.
It is not a weakly prime, because it can be changed into another prime (4023032114461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011516057200 + 2011516057201.
It is an arithmetic number, because the mean of its divisors is an integer number (2011516057201).
Almost surely, 24023032114401 is an apocalyptic number.
It is an amenable number.
4023032114401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023032114401 is an equidigital number, since it uses as much as digits as its factorization.
4023032114401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4023032114401 its reverse (1044112303204), we get a palindrome (5067144417605).
The spelling of 4023032114401 in words is "four trillion, twenty-three billion, thirty-two million, one hundred fourteen thousand, four hundred one".
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