Base | Representation |
---|---|
bin | 100101011110000101… |
… | …100010000010101001 |
3 | 10211211220220001010112 |
4 | 211132011202002221 |
5 | 1124344200322441 |
6 | 30252145224105 |
7 | 2623005451232 |
oct | 453605420251 |
9 | 124756801115 |
10 | 40233214121 |
11 | 16076667291 |
12 | 796a032035 |
13 | 3a42498799 |
14 | 1d39558089 |
15 | 10a72024eb |
hex | 95e1620a9 |
40233214121 has 2 divisors, whose sum is σ = 40233214122. Its totient is φ = 40233214120.
The previous prime is 40233214103. The next prime is 40233214139. The reversal of 40233214121 is 12141233204.
It is a balanced prime because it is at equal distance from previous prime (40233214103) and next prime (40233214139).
It can be written as a sum of positive squares in only one way, i.e., 25193625625 + 15039588496 = 158725^2 + 122636^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40233214121 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (40233214141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20116607060 + 20116607061.
It is an arithmetic number, because the mean of its divisors is an integer number (20116607061).
Almost surely, 240233214121 is an apocalyptic number.
It is an amenable number.
40233214121 is a deficient number, since it is larger than the sum of its proper divisors (1).
40233214121 is an equidigital number, since it uses as much as digits as its factorization.
40233214121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 40233214121 its reverse (12141233204), we get a palindrome (52374447325).
The spelling of 40233214121 in words is "forty billion, two hundred thirty-three million, two hundred fourteen thousand, one hundred twenty-one".
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