Base | Representation |
---|---|
bin | 111010100011101111001… |
… | …011000011110111101111 |
3 | 112020200220120221100110211 |
4 | 322203233023003313233 |
5 | 1011412330110334434 |
6 | 12320351424243251 |
7 | 563505666665314 |
oct | 72435713036757 |
9 | 15220816840424 |
10 | 4024102043119 |
11 | 1311680771374 |
12 | 54ba93770527 |
13 | 2326182a2502 |
14 | dcaa633cd0b |
15 | 6ea21e06464 |
hex | 3a8ef2c3def |
4024102043119 has 2 divisors, whose sum is σ = 4024102043120. Its totient is φ = 4024102043118.
The previous prime is 4024102043111. The next prime is 4024102043141. The reversal of 4024102043119 is 9113402014204.
4024102043119 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4024102043119 - 23 = 4024102043111 is a prime.
It is a super-2 number, since 2×40241020431192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4024102043111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012051021559 + 2012051021560.
It is an arithmetic number, because the mean of its divisors is an integer number (2012051021560).
Almost surely, 24024102043119 is an apocalyptic number.
4024102043119 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024102043119 is an equidigital number, since it uses as much as digits as its factorization.
4024102043119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 4024102043119 in words is "four trillion, twenty-four billion, one hundred two million, forty-three thousand, one hundred nineteen".
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