Base | Representation |
---|---|
bin | 100101011110100111… |
… | …011110011010000101 |
3 | 10211212112122002220112 |
4 | 211132213132122011 |
5 | 1124403440042013 |
6 | 30253104042405 |
7 | 2623144211036 |
oct | 453647363205 |
9 | 124775562815 |
10 | 40242112133 |
11 | 16080694513 |
12 | 7971003405 |
13 | 3a44292892 |
14 | 1d3a7d2a8d |
15 | 10a7dadba8 |
hex | 95e9de685 |
40242112133 has 2 divisors, whose sum is σ = 40242112134. Its totient is φ = 40242112132.
The previous prime is 40242112121. The next prime is 40242112147. The reversal of 40242112133 is 33121124204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20287159489 + 19954952644 = 142433^2 + 141262^2 .
It is a cyclic number.
It is not a de Polignac number, because 40242112133 - 26 = 40242112069 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40242112099 and 40242112108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40242112153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20121056066 + 20121056067.
It is an arithmetic number, because the mean of its divisors is an integer number (20121056067).
Almost surely, 240242112133 is an apocalyptic number.
It is an amenable number.
40242112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
40242112133 is an equidigital number, since it uses as much as digits as its factorization.
40242112133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 40242112133 its reverse (33121124204), we get a palindrome (73363236337).
The spelling of 40242112133 in words is "forty billion, two hundred forty-two million, one hundred twelve thousand, one hundred thirty-three".
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