Base | Representation |
---|---|
bin | 10010010011001110011101… |
… | …00100110001001010111111 |
3 | 12021111012020212021122020011 |
4 | 21021213032210301022333 |
5 | 20233320143132410221 |
6 | 221331215141004051 |
7 | 11322314260624435 |
oct | 1111471644611277 |
9 | 167435225248204 |
10 | 40243014341311 |
11 | 11905a6a50a581 |
12 | 461b4480b3627 |
13 | 195bb913022b2 |
14 | 9d1ab5224d55 |
15 | 49bc2e6011e1 |
hex | 2499ce9312bf |
40243014341311 has 2 divisors, whose sum is σ = 40243014341312. Its totient is φ = 40243014341310.
The previous prime is 40243014341297. The next prime is 40243014341473. The reversal of 40243014341311 is 11314341034204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40243014341311 - 215 = 40243014308543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40243014341111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20121507170655 + 20121507170656.
It is an arithmetic number, because the mean of its divisors is an integer number (20121507170656).
Almost surely, 240243014341311 is an apocalyptic number.
40243014341311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40243014341311 is an equidigital number, since it uses as much as digits as its factorization.
40243014341311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 40243014341311 its reverse (11314341034204), we get a palindrome (51557355375515).
The spelling of 40243014341311 in words is "forty trillion, two hundred forty-three billion, fourteen million, three hundred forty-one thousand, three hundred eleven".
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