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40245321314131 is a prime number
BaseRepresentation
bin10010010011010010110000…
…00101001010111101010011
312021111102012122020222222221
421021221120011022331103
520233334404224023011
6221332240111241511
711322425402566633
oct1111513005127523
9167442178228887
1040245321314131
1111906a4376338a
12461b990819297
13195c16b24917b
149d1c5378a6c3
1549bd16ded971
hex249a5814af53

40245321314131 has 2 divisors, whose sum is σ = 40245321314132. Its totient is φ = 40245321314130.

The previous prime is 40245321314087. The next prime is 40245321314257. The reversal of 40245321314131 is 13141312354204.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40245321314131 - 217 = 40245321183059 is a prime.

It is a super-2 number, since 2×402453213141312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40245321315131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20122660657065 + 20122660657066.

It is an arithmetic number, because the mean of its divisors is an integer number (20122660657066).

Almost surely, 240245321314131 is an apocalyptic number.

40245321314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40245321314131 is an equidigital number, since it uses as much as digits as its factorization.

40245321314131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 40245321314131 its reverse (13141312354204), we get a palindrome (53386633668335).

The spelling of 40245321314131 in words is "forty trillion, two hundred forty-five billion, three hundred twenty-one million, three hundred fourteen thousand, one hundred thirty-one".