Base | Representation |
---|---|
bin | 10010010011010010110000… |
… | …10001011100110100001011 |
3 | 12021111102012212022112110102 |
4 | 21021221120101130310023 |
5 | 20233334411040024003 |
6 | 221332240304240015 |
7 | 11322425442134252 |
oct | 1111513021346413 |
9 | 167442185275412 |
10 | 40245324533003 |
11 | 11906a45561807 |
12 | 461b99191000b |
13 | 195c16bb05325 |
14 | 9d1c53d87799 |
15 | 49bd17337588 |
hex | 249a5845cd0b |
40245324533003 has 2 divisors, whose sum is σ = 40245324533004. Its totient is φ = 40245324533002.
The previous prime is 40245324532981. The next prime is 40245324533023. The reversal of 40245324533003 is 30033542354204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40245324533003 is a prime.
It is a super-2 number, since 2×402453245330032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40245324533023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20122662266501 + 20122662266502.
It is an arithmetic number, because the mean of its divisors is an integer number (20122662266502).
Almost surely, 240245324533003 is an apocalyptic number.
40245324533003 is a deficient number, since it is larger than the sum of its proper divisors (1).
40245324533003 is an equidigital number, since it uses as much as digits as its factorization.
40245324533003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 38.
Adding to 40245324533003 its reverse (30033542354204), we get a palindrome (70278866887207).
The spelling of 40245324533003 in words is "forty trillion, two hundred forty-five billion, three hundred twenty-four million, five hundred thirty-three thousand, three".
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