Search a number
-
+
402514134133 is a prime number
BaseRepresentation
bin1011101101101111011…
…01100100010001110101
31102110221220100121122211
411312313231210101311
523043322104243013
6504525030453421
741036450455066
oct5666755442165
91373856317584
10402514134133
1114578380a601
1266015204271
132bc59478c87
14156a605256d
15a70c4b723d
hex5db7b64475

402514134133 has 2 divisors, whose sum is σ = 402514134134. Its totient is φ = 402514134132.

The previous prime is 402514134107. The next prime is 402514134149. The reversal of 402514134133 is 331431415204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 347041166404 + 55472967729 = 589102^2 + 235527^2 .

It is a cyclic number.

It is not a de Polignac number, because 402514134133 - 225 = 402480579701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 402514134095 and 402514134104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402514134103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201257067066 + 201257067067.

It is an arithmetic number, because the mean of its divisors is an integer number (201257067067).

Almost surely, 2402514134133 is an apocalyptic number.

It is an amenable number.

402514134133 is a deficient number, since it is larger than the sum of its proper divisors (1).

402514134133 is an equidigital number, since it uses as much as digits as its factorization.

402514134133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 402514134133 its reverse (331431415204), we get a palindrome (733945549337).

The spelling of 402514134133 in words is "four hundred two billion, five hundred fourteen million, one hundred thirty-four thousand, one hundred thirty-three".