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40253142110281 is a prime number
BaseRepresentation
bin10010010011100001010100…
…01111001001000001001001
312021112011101200110121102121
421021300222033021001021
520234001413340012111
6221340012130131241
711323123246345612
oct1111605217110111
9167464350417377
1040253142110281
111190a297362281
1246213b3a20b21
13195cb166068b9
149d2396326c09
1549c1237eb871
hex249c2a3c9049

40253142110281 has 2 divisors, whose sum is σ = 40253142110282. Its totient is φ = 40253142110280.

The previous prime is 40253142110267. The next prime is 40253142110287. The reversal of 40253142110281 is 18201124135204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23576462913600 + 16676679196681 = 4855560^2 + 4083709^2 .

It is a cyclic number.

It is not a de Polignac number, because 40253142110281 - 25 = 40253142110249 is a prime.

It is a super-2 number, since 2×402531421102812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40253142110287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20126571055140 + 20126571055141.

It is an arithmetic number, because the mean of its divisors is an integer number (20126571055141).

Almost surely, 240253142110281 is an apocalyptic number.

It is an amenable number.

40253142110281 is a deficient number, since it is larger than the sum of its proper divisors (1).

40253142110281 is an equidigital number, since it uses as much as digits as its factorization.

40253142110281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 34.

Adding to 40253142110281 its reverse (18201124135204), we get a palindrome (58454266245485).

The spelling of 40253142110281 in words is "forty trillion, two hundred fifty-three billion, one hundred forty-two million, one hundred ten thousand, two hundred eighty-one".