Base | Representation |
---|---|
bin | 10010010011100001010100… |
… | …11010101010110110100011 |
3 | 12021112011101220011011001211 |
4 | 21021300222122222312203 |
5 | 20234001420123214301 |
6 | 221340012315010551 |
7 | 11323123314133606 |
oct | 1111605232526643 |
9 | 167464356134054 |
10 | 40253145132451 |
11 | 1190a299036939 |
12 | 46213b4a39a57 |
13 | 195cb17124374 |
14 | 9d23968b233d |
15 | 49c123be7051 |
hex | 249c2a6aada3 |
40253145132451 has 2 divisors, whose sum is σ = 40253145132452. Its totient is φ = 40253145132450.
The previous prime is 40253145132443. The next prime is 40253145132593. The reversal of 40253145132451 is 15423154135204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40253145132451 - 23 = 40253145132443 is a prime.
It is not a weakly prime, because it can be changed into another prime (40253145139451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20126572566225 + 20126572566226.
It is an arithmetic number, because the mean of its divisors is an integer number (20126572566226).
Almost surely, 240253145132451 is an apocalyptic number.
40253145132451 is a deficient number, since it is larger than the sum of its proper divisors (1).
40253145132451 is an equidigital number, since it uses as much as digits as its factorization.
40253145132451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 40.
Adding to 40253145132451 its reverse (15423154135204), we get a palindrome (55676299267655).
The spelling of 40253145132451 in words is "forty trillion, two hundred fifty-three billion, one hundred forty-five million, one hundred thirty-two thousand, four hundred fifty-one".
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