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40253145132593 is a prime number
BaseRepresentation
bin10010010011100001010100…
…11010101010111000110001
312021112011101220011011021002
421021300222122222320301
520234001420123220333
6221340012315011345
711323123314134201
oct1111605232527061
9167464356134232
1040253145132593
111190a299036a58
1246213b4a39b55
13195cb17124453
149d23968b2401
1549c123be70e8
hex249c2a6aae31

40253145132593 has 2 divisors, whose sum is σ = 40253145132594. Its totient is φ = 40253145132592.

The previous prime is 40253145132451. The next prime is 40253145132653. The reversal of 40253145132593 is 39523154135204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31908805868944 + 8344339263649 = 5648788^2 + 2888657^2 .

It is a cyclic number.

It is not a de Polignac number, because 40253145132593 - 222 = 40253140938289 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (40253145137593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20126572566296 + 20126572566297.

It is an arithmetic number, because the mean of its divisors is an integer number (20126572566297).

Almost surely, 240253145132593 is an apocalyptic number.

It is an amenable number.

40253145132593 is a deficient number, since it is larger than the sum of its proper divisors (1).

40253145132593 is an equidigital number, since it uses as much as digits as its factorization.

40253145132593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944000, while the sum is 47.

Adding to 40253145132593 its reverse (39523154135204), we get a palindrome (79776299267797).

The spelling of 40253145132593 in words is "forty trillion, two hundred fifty-three billion, one hundred forty-five million, one hundred thirty-two thousand, five hundred ninety-three".