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402532045471 is a prime number
BaseRepresentation
bin1011101101110001100…
…01111001001010011111
31102111000011001121101201
411312320301321022133
523043341200423341
6504530510420331
741040055634533
oct5667061711237
91374004047351
10402532045471
11145792933666
126601b2016a7
132bc600aa7ba
14156a8595bc3
15a70dd54331
hex5db8c7929f

402532045471 has 2 divisors, whose sum is σ = 402532045472. Its totient is φ = 402532045470.

The previous prime is 402532045423. The next prime is 402532045541. The reversal of 402532045471 is 174540235204.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 402532045471 - 213 = 402532037279 is a prime.

It is a super-3 number, since 3×4025320454713 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 402532045471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402532045771) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201266022735 + 201266022736.

It is an arithmetic number, because the mean of its divisors is an integer number (201266022736).

Almost surely, 2402532045471 is an apocalyptic number.

402532045471 is a deficient number, since it is larger than the sum of its proper divisors (1).

402532045471 is an equidigital number, since it uses as much as digits as its factorization.

402532045471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 37.

The spelling of 402532045471 in words is "four hundred two billion, five hundred thirty-two million, forty-five thousand, four hundred seventy-one".