Base | Representation |
---|---|
bin | 111010100100111111101… |
… | …110001010001100001011 |
3 | 112020211101202210110212102 |
4 | 322210333232022030023 |
5 | 1011423112033440243 |
6 | 12321133501104015 |
7 | 563554326343415 |
oct | 72447756121413 |
9 | 15224352713772 |
10 | 4025453421323 |
11 | 1312204570864 |
12 | 5501b025800b |
13 | 2327a2258c99 |
14 | dcb939d59b5 |
15 | 6eaa08949b8 |
hex | 3a93fb8a30b |
4025453421323 has 2 divisors, whose sum is σ = 4025453421324. Its totient is φ = 4025453421322.
The previous prime is 4025453421307. The next prime is 4025453421329. The reversal of 4025453421323 is 3231243545204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4025453421323 - 24 = 4025453421307 is a prime.
It is not a weakly prime, because it can be changed into another prime (4025453421329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012726710661 + 2012726710662.
It is an arithmetic number, because the mean of its divisors is an integer number (2012726710662).
Almost surely, 24025453421323 is an apocalyptic number.
4025453421323 is a deficient number, since it is larger than the sum of its proper divisors (1).
4025453421323 is an equidigital number, since it uses as much as digits as its factorization.
4025453421323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 4025453421323 its reverse (3231243545204), we get a palindrome (7256696966527).
The spelling of 4025453421323 in words is "four trillion, twenty-five billion, four hundred fifty-three million, four hundred twenty-one thousand, three hundred twenty-three".
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